Engineering Equation Solver Ees Cengel Thermo Iso 【Exclusive • CHECKLIST】

x = (v - v_f)/(v_g - v_f) "Or directly:" x = quality(Fluid$, P=P, h=h_mix) | Mistake | Correction | |---------|-------------| | Forgetting units | Use [kPa] , [C] , [kJ/kg] in comments or EES unit system | | Using P*v = R*T for steam | Use v = volume(Steam, P=P, T=T) | | Isentropic but wrong fluid | s2 = s1 only if reversible & adiabatic | | Confusing W_b sign | EES doesn’t enforce sign convention; write Q - W = ΔU | | Not initializing variables | EES solves iteratively; provide guesses if needed: T2 = 300 | 6. Example Problem: Cengel 7-41 (Isentropic Compression) Problem: Air at 100 kPa, 300 K is compressed isentropically to 1 MPa. Find final temp and work.

"1st law for ideal gas isothermal: Δu=0" Q_in = W_b Most powerful in EES – just set ( s_2 = s_1 ) and EES finds the rest. Engineering Equation Solver EES Cengel Thermo Iso

"Steady-flow compressor work" w_comp_in = h2 - h1 "kJ/kg" x = (v - v_f)/(v_g - v_f) "Or

P1 = 200 [kPa] P2 = P1 T1 = 25 [C] m = 1 [kg] Fluid$ = 'R134a' v1 = volume(Fluid$, P=P1, T=T1) u1 = intEnergy(Fluid$, P=P1, T=T1) h1 = enthalpy(Fluid$, P=P1, T=T1) "1st law for ideal gas isothermal: Δu=0" Q_in

v2 = v1 "Final pressure given" P2 = 500 [kPa] T2 = temperature(Fluid$, P=P2, v=v2) u2 = intEnergy(Fluid$, P=P2, v=v2)

Q_in = m*(u2 - u1) "W=0" Cengel use: Often for ideal gas (( Pv = RT )) or phase change (but constant T in two-phase region implies constant P).