Equilibre D 39-un Solide Soumis A 3 Forces Exercice Corrige Pdf [SAFE]

Now slope of AI: (\tan(\alpha) = \fracy_I - 0x_I - 0 = \frac5 \sin50°2.5 \cos50° = 2 \tan50°).

But ( R_x = R \cos(\alpha) ), ( R_y = R \sin(\alpha) ), where ( \alpha ) = angle of ( R ) with horizontal. Now slope of AI: (\tan(\alpha) = \fracy_I -

So I = (2.5 cos50°, 5 sin50°).

Question: Trouvez les tensions ( T_1 ) et ( T_2 ) dans les câbles. ( R_y = R \sin(\alpha) )